Situation:
- I have
three pieces of wood (¼"x2"x38") stacked
up on each other that I am using to bridge a gap of 36 inches,
so that my train which weighs 20 lb./ft can get across it.
- The
Toy Train Bridge Association (TTBA) codes tell me that I
am only allowed to have a maximum deflection of 0.15 inches.
Problem
Definition
Is there
a problem? If so, what is it?
| Collect
data and analyze information. |
I
take a measurement with the train on the bridge, and
I find that the bridge is sagging about 0.3 inches.
Does it comply with regulations? No . . . so, I have
a problem. The deflection I measured is greater than
what is allowed by the TTBA. I need to fix it. |
Generate
Solutions
One thing
I can do is tinker. I can prop the bridge with a book or something.
But, tinkering is not engineering.
Tenet
of
engineering |
Engineering
is not knowing information, but knowing where to find
the information you need. |
So, I go
to the library and find a book about bridges. In the table
of contents, I notice that there is a chapter entitled Deflections
of Beams. I go to this chapter and find an example problem
called "Simply-Supported Beam Under a Uniform Load."
This looks a lot like my little bridge. In this section, I
find something extremely useful - the following equation that
predicts the deflection of such a beam:

where q
is the force/length of the load, L
is the length of the span, E
is something called the modulus of elasticity, and I
is something called the moment of inertia. I have no idea
what these last two things are, but I can forget about them
for a minute because I realize that this equation is close
to what I need, but not exactly. This equation gives me the
deflection of any point along the beam. What I really need
is just one point - the maximum one. How do I find the equation
for the maximum displacement?
| Tinkering
solution: |
Eyeball
the bridge and guess that it is about midway. |
| Better
solution: |
Graph
the above equation and see where the deflection is greatest.
 |
| Best
solution: |
Use
calculus to find the max. (i.e., find x
value where .) |
We find
that the maximum occurs when x
= L/2.
So we plug this into the deflection equation to get the following
expression for the maximum deflection:

But, we
still have that problem of not knowing what E
and I
are. So, I go back to the bridge book and look them up.
I find
that the elastic modulus (E)
is a constant material property that relates the amount of
stress in a material to how much it is being stretched. There
is also the following table of E values for a few types of
material.
|
Material
|
E
(psi)
|
|
Wood
|
1,750,000
|
|
Aluminum
|
10,000,000
|
|
Titanium
|
15,500,000
|
|
Steel
|
30,000,000
|
I also
find some information about the moment of inertia (I).
It turns out that the moment of inertia does not depend upon
material. Instead, it depends upon the shape of the beam cross-section.
For a rectangular beam, the formula for the moment of inertia
is

where b
is the length of the base of the beam and h
is the height of the beam, as shown in the following figure:

So, now
I know something about all of the terms in my maximum deflection
equation. I decide to plug the moment of inertia equation
into my displacement equation so that I am only dealing with
one equation. By doing this, I get

Let me
check the equation by plugging in values for all the terms.
By stacking my three pieces of wood, I essentially have a
beam with a base of 2 inches and a height of 3 x 0.25 inches
= 0.75 inches as shown in the following figure:

Now when
I plug all of my values into the displacement equation I get

which is
pretty close to what I measured. It looks like the equation
is OK, but how can I solve my problem. I am obviously going
to have to change something about the design of my bridge.
But, what? Lets examine our displacement equation to
find out.
Notice
that I can make vmax smaller by decreasing the numerator or
increasing the denominator. So, now lets generate some
possible solutions in light of this finding.
Possible
Solutions:
| Mathematical
Solution |
Practical
Solution |
| Decrease
q. |
Make
the train lighter. |
| Decrease
L. |
Shorten
the gap. |
| Increase
E. |
Choose
a material with a higher E value. |
| Increase
b. |
Widen
the base. |
| Increase
h. |
Increase
the height. |
Decide
The Course Of Action
Lets
examine the solutions:
| Make
the train lighter. |
I
could shave off sections along the whole length of my
train. But, my train is the whole purpose for having
the bridge, and this seems a little drastic. |
| Shorten
the gap. |
I
cant - thats why I need the bridge. |
| Choose
a different material. |
Right
away I can rule out using titanium, because it is incredibly
expensive and it doesnt give me as high an E
value as steel does (which I know is cheaper.) Perhaps
I could try using pieces of aluminum or steel, though.
Lets see if they will work.
Aluminum:

Steel:

Both
materials will give me allowable deflections! So,
the problem is not a hopeless one.
I
know that one viable solution is to purchase steel
or aluminum pieces. But which one? The steel performs
better than the aluminum does, but maybe it is more
expensive? So, I call around to find some prices.
I find a store that has exactly what I need; they
carry ¼"x2"x38" pieces of both steel
and aluminum. And, guess what? It turns out that steel
is twice as cheap as aluminum. So, I can toss out
the aluminum idea.
Then,
I get a brainstorm. The steel performs so well that
I may even be able to get by with less pieces. What
if I tried using only one or two pieces? This means
that h is now 0.25 or 0.5 inches. Will this work?
Two
Pieces: 
One
Piece: 
Well,
one piece sure wont work. But, I could get by
with two pieces. So, one solution to my problem would
be to buy two pieces of steel to make my bridge. But,
I still have further solutions to examine before I
run out to the store.
|
| Widen
the base of the beam. |
How
could I do this? I cant stretch the wood, but
I could lay the pieces side-by-side, instead of stacking
them up. This would make my base 6 inches wide, but
would decrease the height to 0.25 inches Will this work?

Yikes.
That sure doesnt work.
|
| Increase
the height of the beam. |
How
could I do this? I dont have any more wood pieces
I can stack up. But, what if I stacked them together
then turned them on their side. This would make my base
0.75 inches wide and increase my height 2 inches. Would
this work?

This
would work great. In fact, even if I used one piece
(now my base would change to 0.25 inches) my deflection
would be small enough. Ill show you.

But,
theres one problem. My train needs the bridge
to be 2 inches wide. So, neither of the above solutions
will work. What can I do? How about if I put one piece
on its side and glue another one on top of it to make
a T? This should give me the deflection I need. So,
now I have two solutions:
- Buy
two steel pieces, or
- Make
a T out of two of my wood pieces
I
decide to choose the second, because there is no additional
cost.
|
Implement
the Solution
I glue
my pieces together to make the T. But there is one problem.
I cant get the bridge to stand up. So, I cut away an
inch of the ends of my T-stem (web), and now I can rest the
bridge across the gap just fine.
Evaluate
the Solution
Was my
problem solved? Yes. In fact, I even have a piece of wood
left over for another project. My supposed problem actually
turned out to be a good opportunity.